Search results for "Oscillations"

Physics

CAIE2024

(cid:44)(cid:1)(cid:1)(cid:1)(cid:1)(cid:9)(cid:1)(cid:1)(cid:1)(cid:1)(cid:1)(cid:1)(cid:2)(cid:2)(cid:44) (i) Determine the amplitude, in cm, of the oscillations. amplitude = ....................................................cm [1] (ii) Show that the angular frequency of the oscillations is 3.2 rad s–1. [2] (iii) Calculate the period T of the oscillations. T = .......................................................s [2] (iv) On Fig. 4.3, sketch the variation of h with time t from t = 0 to t = 6.0 s.

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Physics

CAIE2024

Fig. 5.1 shows a pendulum consisting of a metal sphere suspended by a thin string. thin string metal sphere oscillations Fig. 5.1 (not to scale) The sphere undergoes small oscillations about its equilibrium position. The oscillations may be considered to be simple harmonic. Fig. 5.2 shows the variation with time t of the displacement x of the sphere from its equilibrium position.

Question

Physics

CAIE2024

(cid:44)(cid:1)(cid:1)(cid:1)(cid:1)(cid:9)(cid:1)(cid:1)(cid:1)(cid:1)(cid:1)(cid:1)(cid:2)(cid:4)(cid:44) (b) The mass of the sphere is 0.15 kg. (i) State the amplitude of the oscillations. amplitude = ...................................................... m [1] (ii) Determine the angular frequency of the oscillations. angular frequency = .............................................. rad s–1 [2] (iii) Calculate the total energy of the oscillations. total energy = ....................................................... J [2] (c) On Fig. 5.3, sketch the variation with x of the kinetic energy E of the sphere. K

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Physics

CAIE2024

(cid:44)(cid:1)(cid:1)(cid:1)(cid:1)(cid:9)(cid:1)(cid:1)(cid:1)(cid:1)(cid:1)(cid:1)(cid:2)(cid:2)(cid:44) (i) Determine the amplitude, in cm, of the oscillations. amplitude = ....................................................cm [1] (ii) Show that the angular frequency of the oscillations is 3.2 rad s–1. [2] (iii) Calculate the period T of the oscillations. T = .......................................................s [2] (iv) On Fig. 4.3, sketch the variation of h with time t from t = 0 to t = 6.0 s.

Question

Physics

Edexcel2024

Gravitational field strength Gm Ideal gas equation g = r 2 pV = NkT Gravitational potential Stefan-Boltzmann law −Gm L = σAT 4 V = grav r L = 4πr2σT 4 Oscillations Wien’s law Simple harmonic motion λ T = 2.898 × 10−3 m K max F = −k x Space a = −ω2x Intensity x = A cos ωt L v = −Aω sin ωt I = 4πd 2 a = ‒Aω2 cos ωt Redshift of electromagnetic radiation

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Physics

Edexcel2023

Gravitational field strength Gm Ideal gas equation g = r 2 pV = NkT Gravitational potential Stefan‑Boltzmann law −Gm L = σAT 4 V = grav r L = 4πr2σT 4 Oscillations Wien’s law Simple harmonic motion λ T = 2.898 × 10−3 m K max F = −k x Space a = −ω2x Intensity x = A cos ωt L v = −Aω sin ωt I = 4πd 2 a = ‒Aω2 cos ωt Redshift of electromagnetic radiation 1 2π T = = Δλ Δf v f ω z = ≈ ≈ λ f c ω = 2π f Cosmological expansion Simple harmonic oscillator v = H d m

Question

Physics

Edexcel2022

Gravitational field strength Gm Ideal gas equation g = r 2 pV = NkT Gravitational potential Stefan‑Boltzmann law −Gm L = σAT 4 V = grav r L = 4πr2σT 4 Oscillations Wien’s law Simple harmonic motion λ T = 2.898 × 10−3 m K max F = −k x Space a = −ω2x Intensity x = A cos ωt L v = −Aω sin ωt I = 4πd 2 a = ‒Aω2 cos ωt Redshift of electromagnetic radiation

Question

Physics

Edexcel2021

Gravitational field strength Gm Ideal gas equation g = r 2 pV = NkT Gravitational potential Stefan-Boltzmann law −Gm L = σAT 4 V = grav r L = 4πr2σT 4 Oscillations Wien’s law Simple harmonic motion λ T = 2.898 × 10−3 m K max F = −k x Space a = −ω2x Intensity x = A cos ωt L v = −Aω sin ωt I = 4πd 2 a = ‒Aω2 cos ωt Redshift of electromagnetic radiation

Question

Physics

Edexcel2020

Gravitational field strength Gm Ideal gas equation g = r 2 pV = NkT Gravitational potential Stefan-Boltzmann law −Gm L = σAT 4 V = grav r L = 4πr2σT 4 Oscillations Wien’s law Simple harmonic motion λ T = 2.898 × 10−3 m K max F = −k x Space a = −ω2x Intensity x = A cos ωt L v = −Aω sin ωt I = 4πd 2 a = ‒Aω2 cos ωt Redshift of electromagnetic radiation

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