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Physics

CAIE2024

(cid:44)(cid:1)(cid:1)(cid:1)(cid:1)(cid:9)(cid:1)(cid:1)(cid:1)(cid:1)(cid:1)(cid:1)(cid:2)(cid:8)(cid:44) (c) Another capacitor Y is initially uncharged. The fully charged capacitor X in (b) is now connected to capacitor Y, as shown in Fig. 7.2. X Y Fig. 7.2 The capacitance of capacitor Y is 3C. (i) Complete Table 7.1 to show expressions, in terms of Q and V, for the final p.d.s across, and the final charges on, the two capacitors. Use the space below for any working that you need. Table 7.1 X Y final p.d. final charge [3] (ii) State whether the total energy stored in the two capacitors is less than, the same as, or greater than the energy initially stored in capacitor X. ..................................................................................................................................... [1] [Total: 10] © UCLES 2024 (cid:300) (cid:300) (cid:207) (cid:236) (cid:266) (cid:188) (cid:190) (cid:249) (cid:288) (cid:214) (cid:180) (cid:295) (cid:237) (cid:300) (cid:200) (cid:270) (cid:245) (cid:227) (cid:207) (cid:238) (cid:298) (cid:239) (cid:197) (cid:194) (cid:266) (cid:231) (cid:223) (cid:177) (cid:249) (cid:214) (cid:181) (cid:201) (cid:260) (cid:296) (cid:215) (cid:258) 9702/42/O/N/24 [Turn over (cid:293)(cid:197)(cid:197)(cid:277)(cid:181)(cid:245)(cid:261)(cid:213)(cid:197)(cid:229)(cid:293)(cid:261)(cid:261)(cid:213)(cid:261)(cid:245)(cid:245)(cid:213) NIGRAM SIHT NI ETIRW TON OD NIGRAM SIHT NI ETIRW TON OD NIGRAM SIHT NI ETIRW TON OD NIGRAM SIHT NI ETIRW TON OD NIGRAM SIHT NI ETIRW TON OD PMT * 0000800000018 *

Question

Physics

CAIE2024

2 capacitors in parallel C = C + C + ...

Question

Physics

CAIE2024

0.01 0.02 0.03 0.04 t / s Fig. 6.3 The maximum energy stored in the capacitor is 0.041 J. (i) Show that the capacitance of C is 570μF. [2] (ii) Determine the resistance of R. resistance = ..................................................... Ω [3] [Total: 11] © UCLES 2024 (cid:300) (cid:300) (cid:207) (cid:223) (cid:266) (cid:288) (cid:190) (cid:250) (cid:288) (cid:211) (cid:180) (cid:286) (cid:237) (cid:291) (cid:200) (cid:296) (cid:245) (cid:228) (cid:207) (cid:237) (cid:298) (cid:267) (cid:197) (cid:232) (cid:266) (cid:227) (cid:222) (cid:292) (cid:249) (cid:285) (cid:182) (cid:242) (cid:258) (cid:300) (cid:215) (cid:258) 9702/41/O/N/24 [Turn over (cid:293)(cid:277)(cid:261)(cid:277)(cid:181)(cid:181)(cid:261)(cid:277)(cid:277)(cid:181)(cid:213)(cid:261)(cid:197)(cid:213)(cid:197)(cid:277)(cid:229)(cid:213) NIGRAM SIHT NI ETIRW TON OD NIGRAM SIHT NI ETIRW TON OD NIGRAM SIHT NI ETIRW TON OD NIGRAM SIHT NI ETIRW TON OD NIGRAM SIHT NI ETIRW TON OD PMT * 0000800000016 *

Question

Physics

CAIE2024

0.01 0.02 0.03 0.04 t / s Fig. 6.3 The maximum energy stored in the capacitor is 0.041 J. (i) Show that the capacitance of C is 570μF. [2] (ii) Determine the resistance of R. resistance = ..................................................... Ω [3] [Total: 11] © UCLES 2024 (cid:300) (cid:300) (cid:207) (cid:224) (cid:266) (cid:189) (cid:190) (cid:250) (cid:288) (cid:219) (cid:180) (cid:288) (cid:237) (cid:272) (cid:200) (cid:258) (cid:245) (cid:226) (cid:207) (cid:256) (cid:298) (cid:263) (cid:197) (cid:177) (cid:266) (cid:241) (cid:222) (cid:194) (cid:252) (cid:264) (cid:182) (cid:273) (cid:258) (cid:296) (cid:215) (cid:258) 9702/43/O/N/24 [Turn over (cid:293)(cid:245)(cid:197)(cid:277)(cid:245)(cid:277)(cid:229)(cid:213)(cid:245)(cid:213)(cid:261)(cid:197)(cid:261)(cid:277)(cid:293)(cid:245)(cid:293)(cid:213) NIGRAM SIHT NI ETIRW TON OD NIGRAM SIHT NI ETIRW TON OD NIGRAM SIHT NI ETIRW TON OD NIGRAM SIHT NI ETIRW TON OD NIGRAM SIHT NI ETIRW TON OD PMT * 0000800000016 *

Question

Physics

Edexcel2024

Capacitance Q C = V  PMT Nuclear and particle physics Radioactive decay A = λN In a magnetic field dN p = −λN r = dt BQ ln 2 λ = t ½ Thermodynamics N = N e−λt Heating 0 A = A e−λt

Question

Physics

Edexcel2024

Turn over PMT (c) The student connects the filament bulb in the circuit shown below. The capacitor is initially uncharged and has a capacitance of 1.2 F. The resistance of the filament bulb is 5 Ω.

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Physics

CAIE2024

2 capacitors in parallel C = C + C + ...

Question

Physics

CAIE2024

2 capacitors in parallel C = C + C + ...

Question

Physics

CAIE2024

(a) Define the capacitance of a parallel‑plate capacitor. ................................................................................................................................................... ................................................................................................................................................... ............................................................................................................................................. [2] (b) An initially uncharged capacitor X, of capacitance C, is gradually charged so that the final potential difference (p.d.) between its plates is V and the final charge is Q. (i) On Fig. 7.1, sketch the variation of charge with p.d. for capacitor X as the p.d. increases from 0 to V. Q charge

Question

Physics

CAIE2023

2 capacitors in parallel C = C + C + ....

Question

Physics

CAIE2023

the capacitance of the capacitor. capacitance = F [4] (c) A second capacitor is now connected in parallel with the resistor R and the first capacitor. On Fig. 4.3, draw a line to show the variation with time t of the potential differenceV across the resistor. [1] © UCLES 2005 9702/04/SPECIMEN PAPER [Turn over PPPMMMTTT For

Question

Physics

Edexcel2023

Calc(cid:88)late the capacitance of the capacitor. !"# 11111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 11111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 11111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 11111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 11111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 11111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 11111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 Capacitance (cid:32)

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Physics

Edexcel2023

Capacitance Q C = V *P71915A02628* DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA AERA SIHT NI ETIRW TON OD AERA SIHT NI ETIRW TON OD AERA SIHT NI ETIRW TON OD PMT Nuclear and particle physics Radioactive decay A = λN In a magnetic field dN p = −λN r = dt BQ ln 2 λ = t ½ Thermodynamics N = N e−λt Heating 0 A = A e−λt

Question

Physics

Edexcel2023

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&*+)#!/1!*!2+%&!)2,#5 BC-+5/'8-&'D*%#+,-"'?'E'?'05&>F G A capacitor of 50 μC is charged to a potential difference of 12 V. ! 84#!#+#.3(!&/.#-!/+!&4#!)4*.3#-!)*6*)%&/.!%+!9/20#!%$!3%'#+!,( ' ' !' 0.5 × 50 × 10:; × 122

Question

Physics

Edexcel2022

10 20 30 Time / ms Determine a value for the capacitance of the capacitor. resistance of R = 2.2 kΩ (3) ................................................................................................................................................................................................................................................... ................................................................................................................................................................................................................................................... ................................................................................................................................................................................................................................................... ................................................................................................................................................................................................................................................... ................................................................................................................................................................................................................................................... ................................................................................................................................................................................................................................................... ................................................................................................................................................................................................................................................... Capacitance = ....................................................... (Total for Question 14 = 8 marks) 

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Physics

Edexcel2022

Capacitance Q C = V 

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Physics

Edexcel2021

Q At a potential difference V a small charge ∆Q is added to the capacitor. This results in

Question

Physics

Edexcel2021

C V × ∆Q

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Physics

Edexcel2021

Capacitance Q C = V

Question

Physics

Edexcel2021

*P67096A01432* PMT (b) A parallel plate capacitor consists of a thin layer of insulator of thickness d between two plates of conducting material of area A. insulator conducting material A d The capacitor has a capacitance 0.1 μF and is charged to a p.d. of 100 V by connecting it to an electrical supply. The capacitor is then disconnected from the supply and the p.d. between the two plates slowly decreases. This is because the insulator is not perfect and a small charge can flow through it. The graph shows how the p.d. varies with time. p.d. / V 100

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Physics

Edexcel2021

The graph shows how the potential difference V across the capacitor varies with the charge Q on the capacitor. V V

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Physics

Edexcel2020

C = 1.5 μF

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Physics

Edexcel2020

Capacitance Q C = V

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Physics

CAIE2016

the capacitance of the capacitor. capacitance = ............................................................ F [4] (c) A second capacitor is now connected in parallel with the resistor R and the fi rst capacitor. On Fig. 10.3, draw a line to show the variation with time t of the potential difference V across the resistor. [1] [Total: 10] © UCLES 2014 9702/04/SP/16 [Turn over PPMMTT

Question

Physics

CAIE2016

2 capacitors in parallel C = C + C + . . .

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